5/6(3x-2)=2/3(x+1)

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Solution for 5/6(3x-2)=2/3(x+1) equation: 



5/6(3x-2)=2/3(x+1)

We move all terms to the left:

5/6(3x-2)-(2/3(x+1))=0



Domain of the equation: 6(3x-2)!=0

x∈R





Domain of the equation: 3(x+1))!=0

x∈R



We calculate fractions


(15xx/(6(3x-2)*3(x+1)))+(-12x3/(6(3x-2)*3(x+1)))=0



We calculate terms in parentheses: +(15xx/(6(3x-2)*3(x+1))), so:

15xx/(6(3x-2)*3(x+1))

We multiply all the terms by the denominator


15xx

Back to the equation:

+(15xx)





We calculate terms in parentheses: +(-12x3/(6(3x-2)*3(x+1))), so:

-12x3/(6(3x-2)*3(x+1))

We multiply all the terms by the denominator


-12x3

We add all the numbers together, and all the variables

-12x^3

We do not support expression: x^3

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