5/6(6x-8)=1/3(9x+12)

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Solution for 5/6(6x-8)=1/3(9x+12) equation: 



5/6(6x-8)=1/3(9x+12)

We move all terms to the left:

5/6(6x-8)-(1/3(9x+12))=0



Domain of the equation: 6(6x-8)!=0

x∈R





Domain of the equation: 3(9x+12))!=0

x∈R



We calculate fractions


(15x9/(6(6x-8)*3(9x+12)))+(-6x6/(6(6x-8)*3(9x+12)))=0



We calculate terms in parentheses: +(15x9/(6(6x-8)*3(9x+12))), so:

15x9/(6(6x-8)*3(9x+12))

We multiply all the terms by the denominator


15x9

We add all the numbers together, and all the variables

15x^9

We do not support expression: x^9

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