5/6(x-12)=1/3x

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Solution for 5/6(x-12)=1/3x equation: 



5/6(x-12)=1/3x

We move all terms to the left:

5/6(x-12)-(1/3x)=0



Domain of the equation: 6(x-12)!=0

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

5/6(x-12)-(+1/3x)=0

We get rid of parentheses

5/6(x-12)-1/3x=0

We calculate fractions


15x/(18x^2-216x)+(-6xx/(18x^2-216x)=0



We calculate terms in parentheses: +(-6xx/(18x^2-216x), so:

-6xx/(18x^2-216x

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)



We get rid of parentheses

15x/(18x^2-216x)-6xx=0

We multiply all the terms by the denominator


15x-6xx*(18x^2-216x)=0

We multiply parentheses

-108x^3+1296x^2+15x=0

We do not support expression: x^3

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