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5/6+2-u=1/6u
We move all terms to the left:
5/6+2-u-(1/6u)=0
Domain of the equation: 6u)!=0We add all the numbers together, and all the variables
u!=0/1
u!=0
u∈R
-u-(+1/6u)+2+5/6=0
We add all the numbers together, and all the variables
-1u-(+1/6u)+2+5/6=0
We get rid of parentheses
-1u-1/6u+2+5/6=0
We calculate fractions
-1u+2=0
We move all terms containing u to the left, all other terms to the right
-u=-2
u=-2/-1
u=+2
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