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5/6a+4=2/3a+6
We move all terms to the left:
5/6a+4-(2/3a+6)=0
Domain of the equation: 6a!=0
a!=0/6
a!=0
a∈R
Domain of the equation: 3a+6)!=0We get rid of parentheses
a∈R
5/6a-2/3a-6+4=0
We calculate fractions
15a/18a^2+(-12a)/18a^2-6+4=0
We add all the numbers together, and all the variables
15a/18a^2+(-12a)/18a^2-2=0
We multiply all the terms by the denominator
15a+(-12a)-2*18a^2=0
Wy multiply elements
-36a^2+15a+(-12a)=0
We get rid of parentheses
-36a^2+15a-12a=0
We add all the numbers together, and all the variables
-36a^2+3a=0
a = -36; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-36)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-36}=\frac{-6}{-72} =1/12 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-36}=\frac{0}{-72} =0 $
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