5/6b=2-11/12b

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Solution for 5/6b=2-11/12b equation:



5/6b=2-11/12b
We move all terms to the left:
5/6b-(2-11/12b)=0
Domain of the equation: 6b!=0
b!=0/6
b!=0
b∈R
Domain of the equation: 12b)!=0
b!=0/1
b!=0
b∈R
We add all the numbers together, and all the variables
5/6b-(-11/12b+2)=0
We get rid of parentheses
5/6b+11/12b-2=0
We calculate fractions
60b/72b^2+66b/72b^2-2=0
We multiply all the terms by the denominator
60b+66b-2*72b^2=0
We add all the numbers together, and all the variables
126b-2*72b^2=0
Wy multiply elements
-144b^2+126b=0
a = -144; b = 126; c = 0;
Δ = b2-4ac
Δ = 1262-4·(-144)·0
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-126}{2*-144}=\frac{-252}{-288} =7/8 $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+126}{2*-144}=\frac{0}{-288} =0 $

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