5/6f-1/12f=3/4f+1

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Solution for 5/6f-1/12f=3/4f+1 equation: 


f in (-oo:+oo)

(5/6)*f-((1/12)*f) = (3/4)*f+1 // - (3/4)*f+1

(5/6)*f-((1/12)*f)-((3/4)*f)-1 = 0

(5/6)*f+(-1/12)*f+(-3/4)*f-1 = 0

-1 = 0

f belongs to the empty set

f belongs to the empty set

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