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5/6t+2/3t=3
We move all terms to the left:
5/6t+2/3t-(3)=0
Domain of the equation: 6t!=0
t!=0/6
t!=0
t∈R
Domain of the equation: 3t!=0We calculate fractions
t!=0/3
t!=0
t∈R
15t/18t^2+12t/18t^2-3=0
We multiply all the terms by the denominator
15t+12t-3*18t^2=0
We add all the numbers together, and all the variables
27t-3*18t^2=0
Wy multiply elements
-54t^2+27t=0
a = -54; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·(-54)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*-54}=\frac{-54}{-108} =1/2 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*-54}=\frac{0}{-108} =0 $
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