5/6x+1/2=4+2/3x

Solution for 5/6x+1/2=4+2/3x equation:

5/6x+1/2=4+2/3x

We move all terms to the left:

5/6x+1/2-(4+2/3x)=0


Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

5/6x-(2/3x+4)+1/2=0

We get rid of parentheses

5/6x-2/3x-4+1/2=0

We calculate fractions


54x^2/72x^2+60x/72x^2+(-48x)/72x^2-4=0

We multiply all the terms by the denominator


54x^2+60x+(-48x)-4*72x^2=0

Wy multiply elements

54x^2-288x^2+60x+(-48x)=0

We get rid of parentheses

54x^2-288x^2+60x-48x=0

We add all the numbers together, and all the variables

-234x^2+12x=0

a = -234; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-234)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-234}=\frac{-24}{-468}
=2/39
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-234}=\frac{0}{-468}
=0
$