5/6x+1/8x=7/8+x

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Solution for 5/6x+1/8x=7/8+x equation:



5/6x+1/8x=7/8+x
We move all terms to the left:
5/6x+1/8x-(7/8+x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 8+x)!=0
We move all terms containing x to the left, all other terms to the right
x)!=-8
x!=-8/1
x!=-8
x∈R
We add all the numbers together, and all the variables
5/6x+1/8x-(+x+7/8)=0
We get rid of parentheses
5/6x+1/8x-x-7/8=0
We calculate fractions
-x+2560x/3072x^2+6x/3072x^2+(-42x)/3072x^2=0
We add all the numbers together, and all the variables
-1x+2560x/3072x^2+6x/3072x^2+(-42x)/3072x^2=0
We multiply all the terms by the denominator
-1x*3072x^2+2560x+6x+(-42x)=0
We add all the numbers together, and all the variables
2566x-1x*3072x^2+(-42x)=0
Wy multiply elements
-3072x^3+2566x+(-42x)=0
We get rid of parentheses
-3072x^3+2566x-42x=0
We do not support expression: x^3

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