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5/6x+90=x
We move all terms to the left:
5/6x+90-(x)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
-1x+5/6x+90=0
We multiply all the terms by the denominator
-1x*6x+90*6x+5=0
Wy multiply elements
-6x^2+540x+5=0
a = -6; b = 540; c = +5;
Δ = b2-4ac
Δ = 5402-4·(-6)·5
Δ = 291720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{291720}=\sqrt{4*72930}=\sqrt{4}*\sqrt{72930}=2\sqrt{72930}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(540)-2\sqrt{72930}}{2*-6}=\frac{-540-2\sqrt{72930}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(540)+2\sqrt{72930}}{2*-6}=\frac{-540+2\sqrt{72930}}{-12} $
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