5/6x-(1/5)x+4=(7/10)x

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Solution for 5/6x-(1/5)x+4=(7/10)x equation: 



5/6x-(1/5)x+4=(7/10)x

We move all terms to the left:

5/6x-(1/5)x+4-((7/10)x)=0



Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R





Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 10)x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

5/6x-(+1/5)x-((+7/10)x)+4=0

We multiply parentheses

-x^2+5/6x-((+7/10)x)+4=0

We calculate fractions


-x^2+50x/60x^2+(-((+7*6x)/60x^2+4=0

We add all the numbers together, and all the variables

-1x^2+50x/60x^2+(-((+7*6x)/60x^2+4=0

We calculate fractions

We do not support expression: x^4

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