5/6x-1/6y=2;1/2x+3/4y=-1/2

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Solution for 5/6x-1/6y=2;1/2x+3/4y=-1/2 system of equations: 


  • /| (5/6)*x-((1/6)*y)-2 = 0| (1/2)*x+(3/4)*y-(-1/2) = 0
  • We try to solve the equation: (5/6)*x-((1/6)*y)-2 = 0
  • 5/6*x-1/6*y-2 = 0 // - 5/6*x-2
  • -1/6*y = -(5/6*x-2) // : -1/6
  • y = (-(5/6*x-2))/(-1/6)
  • y = -6*(2-(5/6*x))
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (1/2)*x-6*(3/4)*(2-(5/6*x))-(-1/2) = 0| y = -6*(2-(5/6*x))
  • x/2-9/2*(2-5/6*x)+1/2 = 0
  • 17/4*x-9+1/2 = 0
  • 17/4*x-17/2 = 0
  • 17/4*x-17/2 = 0 // + 17/2
  • 17/4*x = 17/2 // : 17/4
  • x = 17/2/17/4
  • x = 2
  • We insert the solution into one of the initial equations of our system of equations
  • For y = -6*(2-(5/6*x)): 
  • y = -6*(2-(5/6*2))
  • y = -6*(2-5/3)
  • y = -6*1/3
  • y = -2
  • We get a system of equations:
  • /| y = -2| x = 2

 

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