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5/6x-12=-3/2x
We move all terms to the left:
5/6x-12-(-3/2x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 2x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
5/6x+3/2x-12=0
We calculate fractions
10x/12x^2+18x/12x^2-12=0
We multiply all the terms by the denominator
10x+18x-12*12x^2=0
We add all the numbers together, and all the variables
28x-12*12x^2=0
Wy multiply elements
-144x^2+28x=0
a = -144; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-144)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-144}=\frac{-56}{-288} =7/36 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-144}=\frac{0}{-288} =0 $
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