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5/6x-3/8x=7/12
We move all terms to the left:
5/6x-3/8x-(7/12)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
5/6x-3/8x-(+7/12)=0
We get rid of parentheses
5/6x-3/8x-7/12=0
We calculate fractions
(-2688x^2)/576x^2+480x/576x^2+(-216x)/576x^2=0
We multiply all the terms by the denominator
(-2688x^2)+480x+(-216x)=0
We get rid of parentheses
-2688x^2+480x-216x=0
We add all the numbers together, and all the variables
-2688x^2+264x=0
a = -2688; b = 264; c = 0;
Δ = b2-4ac
Δ = 2642-4·(-2688)·0
Δ = 69696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{69696}=264$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(264)-264}{2*-2688}=\frac{-528}{-5376} =11/112 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(264)+264}{2*-2688}=\frac{0}{-5376} =0 $
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