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5/6x=10-x
We move all terms to the left:
5/6x-(10-x)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
5/6x-(-1x+10)=0
We get rid of parentheses
5/6x+1x-10=0
We multiply all the terms by the denominator
1x*6x-10*6x+5=0
Wy multiply elements
6x^2-60x+5=0
a = 6; b = -60; c = +5;
Δ = b2-4ac
Δ = -602-4·6·5
Δ = 3480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3480}=\sqrt{4*870}=\sqrt{4}*\sqrt{870}=2\sqrt{870}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-2\sqrt{870}}{2*6}=\frac{60-2\sqrt{870}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+2\sqrt{870}}{2*6}=\frac{60+2\sqrt{870}}{12} $
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