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5/6x=20x
We move all terms to the left:
5/6x-(20x)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
-20x+5/6x=0
We multiply all the terms by the denominator
-20x*6x+5=0
Wy multiply elements
-120x^2+5=0
a = -120; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-120)·5
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{6}}{2*-120}=\frac{0-20\sqrt{6}}{-240} =-\frac{20\sqrt{6}}{-240} =-\frac{\sqrt{6}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{6}}{2*-120}=\frac{0+20\sqrt{6}}{-240} =\frac{20\sqrt{6}}{-240} =\frac{\sqrt{6}}{-12} $
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