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5/6x=4/2x+4
We move all terms to the left:
5/6x-(4/2x+4)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 2x+4)!=0We get rid of parentheses
x∈R
5/6x-4/2x-4=0
We calculate fractions
10x/12x^2+(-24x)/12x^2-4=0
We multiply all the terms by the denominator
10x+(-24x)-4*12x^2=0
Wy multiply elements
-48x^2+10x+(-24x)=0
We get rid of parentheses
-48x^2+10x-24x=0
We add all the numbers together, and all the variables
-48x^2-14x=0
a = -48; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·(-48)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*-48}=\frac{0}{-96} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*-48}=\frac{28}{-96} =-7/24 $
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