5/7(-6x-3)=1

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Solution for 5/7(-6x-3)=1 equation: 



5/7(-6x-3)=1

We move all terms to the left:

5/7(-6x-3)-(1)=0



Domain of the equation: 7(-6x-3)!=0

x∈R



We multiply all the terms by the denominator


-1*7(-6x-3)+5=0

Wy multiply elements

-7x(-+5=0

We use the square of the difference formula

-7x(-5=0

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