5/7(14n-35)=10

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Solution for 5/7(14n-35)=10 equation: 



5/7(14n-35)=10

We move all terms to the left:

5/7(14n-35)-(10)=0



Domain of the equation: 7(14n-35)!=0

n∈R



We multiply all the terms by the denominator


-10*7(14n-35)+5=0

Wy multiply elements

-70n(1+5=0

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