5/7(21x-14)=35

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Solution for 5/7(21x-14)=35 equation: 



5/7(21x-14)=35

We move all terms to the left:

5/7(21x-14)-(35)=0



Domain of the equation: 7(21x-14)!=0

x∈R



We multiply all the terms by the denominator


-35*7(21x-14)+5=0

Wy multiply elements

-245x(2+5=0

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