5/7(6a+2)=41

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Solution for 5/7(6a+2)=41 equation: 



5/7(6a+2)=41

We move all terms to the left:

5/7(6a+2)-(41)=0



Domain of the equation: 7(6a+2)!=0

a∈R



We multiply all the terms by the denominator


-41*7(6a+2)+5=0

Wy multiply elements

-287a(6+5=0

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