5/7c=35

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Solution for 5/7c=35 equation: 



5/7c=35

We move all terms to the left:

5/7c-(35)=0



Domain of the equation: 7c!=0

c!=0/7

c!=0

c∈R



We multiply all the terms by the denominator


-35*7c+5=0

Wy multiply elements

-245c+5=0

We move all terms containing c to the left, all other terms to the right

-245c=-5

c=-5/-245

c=1/49

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