5/7h=35

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Solution for 5/7h=35 equation: 



5/7h=35

We move all terms to the left:

5/7h-(35)=0



Domain of the equation: 7h!=0

h!=0/7

h!=0

h∈R



We multiply all the terms by the denominator


-35*7h+5=0

Wy multiply elements

-245h+5=0

We move all terms containing h to the left, all other terms to the right

-245h=-5

h=-5/-245

h=1/49

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