5/7x+21=4

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Solution for 5/7x+21=4 equation: 



5/7x+21=4

We move all terms to the left:

5/7x+21-(4)=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



We add all the numbers together, and all the variables

5/7x+17=0

We multiply all the terms by the denominator


17*7x+5=0

Wy multiply elements

119x+5=0

We move all terms containing x to the left, all other terms to the right

119x=-5

x=-5/119

x=-5/119

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