5/7x-4/3=(3x+1)/2

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Solution for 5/7x-4/3=(3x+1)/2 equation: 


x in (-oo:+oo)

(5/7)*x-(4/3) = (3*x+1)/2 // - (3*x+1)/2

(5/7)*x-((3*x+1)/2)-(4/3) = 0

(5/7)*x-((3*x+1)/2)-4/3 = 0

(-1*(3*x+1))/2+(5*x)/7-4/3 = 0

(-1*3*7*(3*x+1))/(2*3*7)+(2*3*5*x)/(2*3*7)+(-4*2*7)/(2*3*7) = 0

2*3*5*x-1*3*7*(3*x+1)-4*2*7 = 0

-33*x-56-21 = 0

-33*x-77 = 0

(-33*x-77)/(2*3*7) = 0

(-33*x-77)/(2*3*7) = 0 // * 2*3*7

-33*x-77 = 0

-33*x-77 = 0 // + 77

-33*x = 77 // : -33

x = 77/(-33)

x = -7/3

x = -7/3

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