5/8(2y+3)+5/4y=3/4(4y+1)

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Solution for 5/8(2y+3)+5/4y=3/4(4y+1) equation: 



5/8(2y+3)+5/4y=3/4(4y+1)

We move all terms to the left:

5/8(2y+3)+5/4y-(3/4(4y+1))=0



Domain of the equation: 8(2y+3)!=0

y∈R





Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R





Domain of the equation: 4(4y+1))!=0

y∈R



We calculate fractions


320y^2/(8(2y+3)*4y*4(4y+1)))+(160y^22/(8(2y+3)*4y*4(4y+1)))+(-(3*8(2y+3)*4y)/(8(2y+3)*4y*4(4y+1)))=0



We calculate terms in parentheses: -(3*8(2y+3)*4y)/(8(2y+3)*4y*4(4y+1))), so:

3*8(2y+3)*4y)/(8(2y+3)*4y*4(4y+1))

We multiply all the terms by the denominator


3*8(2y+3)*4y)

Wy multiply elements

96y^2(2

Back to the equation:

-(96y^2(2)



We do not support eypression: y^22

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