5/8c+1/4=1/2c

Solution for 5/8c+1/4=1/2c equation:

5/8c+1/4=1/2c

We move all terms to the left:

5/8c+1/4-(1/2c)=0


Domain of the equation: 8c!=0

c!=0/8

c!=0

c∈R



Domain of the equation: 2c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

5/8c-(+1/2c)+1/4=0

We get rid of parentheses

5/8c-1/2c+1/4=0

We calculate fractions


32c^2/256c^2+160c/256c^2+(-128c)/256c^2=0

We multiply all the terms by the denominator


32c^2+160c+(-128c)=0

We get rid of parentheses

32c^2+160c-128c=0

We add all the numbers together, and all the variables

32c^2+32c=0

a = 32; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·32·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*32}=\frac{-64}{64}
=-1
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*32}=\frac{0}{64}
=0
$