5/8v=40;v=64

Solution for 5/8v=40;v=64 equation:

5/8v=40v=64

We move all terms to the left:

5/8v-(40v)=0


Domain of the equation: 8v!=0

v!=0/8

v!=0

v∈R


We add all the numbers together, and all the variables

-40v+5/8v=0

We multiply all the terms by the denominator


-40v*8v+5=0

Wy multiply elements

-320v^2+5=0

a = -320; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-320)·5
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*-320}=\frac{-80}{-640}
=1/8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*-320}=\frac{80}{-640}
=-1/8
$