5/8x+-2=1/2x-4

Solution for 5/8x+-2=1/2x-4 equation:

5/8x+-2=1/2x-4

We move all terms to the left:

5/8x+-2-(1/2x-4)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 2x-4)!=0

x∈R


We add all the numbers together, and all the variables

5/8x-(1/2x-4)=0

We get rid of parentheses

5/8x-1/2x+4=0

We calculate fractions


10x/16x^2+(-8x)/16x^2+4=0

We multiply all the terms by the denominator


10x+(-8x)+4*16x^2=0

Wy multiply elements

64x^2+10x+(-8x)=0

We get rid of parentheses

64x^2+10x-8x=0

We add all the numbers together, and all the variables

64x^2+2x=0

a = 64; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·64·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*64}=\frac{-4}{128}
=-1/32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*64}=\frac{0}{128}
=0
$