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5/8x-5=1/2x-2
We move all terms to the left:
5/8x-5-(1/2x-2)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 2x-2)!=0We get rid of parentheses
x∈R
5/8x-1/2x+2-5=0
We calculate fractions
10x/16x^2+(-8x)/16x^2+2-5=0
We add all the numbers together, and all the variables
10x/16x^2+(-8x)/16x^2-3=0
We multiply all the terms by the denominator
10x+(-8x)-3*16x^2=0
Wy multiply elements
-48x^2+10x+(-8x)=0
We get rid of parentheses
-48x^2+10x-8x=0
We add all the numbers together, and all the variables
-48x^2+2x=0
a = -48; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-48)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-48}=\frac{-4}{-96} =1/24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-48}=\frac{0}{-96} =0 $
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