5/9(f+32)=25

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Solution for 5/9(f+32)=25 equation: 



5/9(f+32)=25

We move all terms to the left:

5/9(f+32)-(25)=0



Domain of the equation: 9(f+32)!=0

f∈R



We multiply all the terms by the denominator


-25*9(f+32)+5=0

Wy multiply elements

-225f(f+5=0

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