5/9(f-32)=100

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Solution for 5/9(f-32)=100 equation: 



5/9(f-32)=100

We move all terms to the left:

5/9(f-32)-(100)=0



Domain of the equation: 9(f-32)!=0

f∈R



We multiply all the terms by the denominator


-100*9(f-32)+5=0

Wy multiply elements

-900f(f+5=0

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