5/9(t+3)=40

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Solution for 5/9(t+3)=40 equation: 



5/9(t+3)=40

We move all terms to the left:

5/9(t+3)-(40)=0



Domain of the equation: 9(t+3)!=0

t∈R



We multiply all the terms by the denominator


-40*9(t+3)+5=0

Wy multiply elements

-360t(t+5=0

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