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5/9(x+1)=5/8(x-2)
We move all terms to the left:
5/9(x+1)-(5/8(x-2))=0
Domain of the equation: 9(x+1)!=0
x∈R
Domain of the equation: 8(x-2))!=0We calculate fractions
x∈R
(40xx/(9(x+1)*8(x-2)))+(-45xx/(9(x+1)*8(x-2)))=0
We calculate terms in parentheses: +(40xx/(9(x+1)*8(x-2))), so:
40xx/(9(x+1)*8(x-2))
We multiply all the terms by the denominator
40xx
Back to the equation:
+(40xx)
We calculate terms in parentheses: +(-45xx/(9(x+1)*8(x-2))), so:We get rid of parentheses
-45xx/(9(x+1)*8(x-2))
We multiply all the terms by the denominator
-45xx
Back to the equation:
+(-45xx)
40xx-45xx=0
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