If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5/9e-11/3e=3
We move all terms to the left:
5/9e-11/3e-(3)=0
Domain of the equation: 9e!=0
e!=0/9
e!=0
e∈R
Domain of the equation: 3e!=0We calculate fractions
e!=0/3
e!=0
e∈R
15e/27e^2+(-99e)/27e^2-3=0
We multiply all the terms by the denominator
15e+(-99e)-3*27e^2=0
Wy multiply elements
-81e^2+15e+(-99e)=0
We get rid of parentheses
-81e^2+15e-99e=0
We add all the numbers together, and all the variables
-81e^2-84e=0
a = -81; b = -84; c = 0;
Δ = b2-4ac
Δ = -842-4·(-81)·0
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-84}{2*-81}=\frac{0}{-162} =0 $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+84}{2*-81}=\frac{168}{-162} =-1+1/27 $
| 5x-43=7(x-7) | | n^2-n=5 | | 29=x/5+8 | | (1/27)^-3v=81 | | N=6x35+4 | | 8b-12-4b-19=37 | | 1/9x^2-4=0 | | 43a+10-26a=27* | | 0.79+0.56y=0.4764 | | 3y-2(y-19)=9y-3(9-y) | | 10-x=4x+12-3x | | 3x/7+2=15 | | 248/4=341/x | | -2(x+3)=x+9* | | x^2-5*x=0 | | 5(7+3x)=40 | | 2x^2+9x-341=0 | | 5/3+7x-2x1/3(9x+2)=0 | | x^2+x-2=10x^2-40x+40 | | X/5=x/4+2 | | x/7+5=16 | | 1-9r=10-8r | | -41=-2/5(45+60)+n | | -35=-5x+10+5x-15x | | (9x+36)=(25x+16) | | 5n+7=7(n | | 8(x+2)-9x=16-(x-1) | | 9x-4x+3=16 | | 10+6-3m=-9+2m | | 8x+7-5x=3x+1 | | (3x+6)2=(5x+4)2 | | 5-6n=-7-3n |