5/9f-32=25

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Solution for 5/9f-32=25 equation: 



5/9f-32=25

We move all terms to the left:

5/9f-32-(25)=0



Domain of the equation: 9f!=0

f!=0/9

f!=0

f∈R



We add all the numbers together, and all the variables

5/9f-57=0

We multiply all the terms by the denominator


-57*9f+5=0

Wy multiply elements

-513f+5=0

We move all terms containing f to the left, all other terms to the right

-513f=-5

f=-5/-513

f=5/513

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