5/b-1+3/2b+3=0

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Solution for 5/b-1+3/2b+3=0 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

(3/2)*b+5/b-1+3 = 0

3/2*b^1+5*b^-1+2*b^0 = 0

(3/2*b^2+2*b^1+5*b^0)/(b^1) = 0 // * b^2

b^1*(3/2*b^2+2*b^1+5*b^0) = 0

b^1

(3/2)*b^2+2*b+5 = 0

(3/2)*b^2+2*b+5 = 0

DELTA = 2^2-(4*5*(3/2))

DELTA = -26

DELTA < 0

b in { } 

b belongs to the empty set

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