5/h-7/12=-3/4h-13/6

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Solution for 5/h-7/12=-3/4h-13/6 equation:


D( h )

h = 0

h = 0

h = 0

h in (-oo:0) U (0:+oo)

5/h-(7/12) = (-3/4)*h-(13/6) // - (-3/4)*h-(13/6)

5/h-((-3/4)*h)-(7/12)+13/6 = 0

(3/4)*h+5/h-7/12+13/6 = 0

3/4*h^1+5*h^-1+19/12*h^0 = 0

(3/4*h^2+19/12*h^1+5*h^0)/(h^1) = 0 // * h^2

h^1*(3/4*h^2+19/12*h^1+5*h^0) = 0

h^1

(3/4)*h^2+(19/12)*h+5 = 0

(3/4)*h^2+(19/12)*h+5 = 0

DELTA = (19/12)^2-(4*5*(3/4))

DELTA = -1799/144

DELTA < 0

h in { }

h belongs to the empty set

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