5/m-1+7/1-m

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Solution for 5/m-1+7/1-m equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

5/m-m+7/1-1 = 0

5/m-m-1+7 = 0

5*m^-1-1*m^1+6*m^0 = 0

(6*m^1-1*m^2+5*m^0)/(m^1) = 0 // * m^2

m^1*(6*m^1-1*m^2+5*m^0) = 0

m^1

6*m-m^2+5 = 0

6*m-m^2+5 = 0

DELTA = 6^2-(-1*4*5)

DELTA = 56

DELTA > 0

m = (56^(1/2)-6)/(-1*2) or m = (-56^(1/2)-6)/(-1*2)

m = (2*14^(1/2)-6)/(-2) or m = (-2*14^(1/2)-6)/(-2)

m in { (2*14^(1/2)-6)/(-2), (-2*14^(1/2)-6)/(-2)} 

m in { (2*14^(1/2)-6)/(-2), (-2*14^(1/2)-6)/(-2) }

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