5/n-1=-n+19/2

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Solution for 5/n-1=-n+19/2 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

5/n-1 = 19/2-n // - 19/2-n

n+5/n-(19/2)-1 = 0

n+5/n-19/2-1 = 0

1*n^1+5*n^-1-21/2*n^0 = 0

(1*n^2-21/2*n^1+5*n^0)/(n^1) = 0 // * n^2

n^1*(1*n^2-21/2*n^1+5*n^0) = 0

n^1

n^2+(-21/2)*n+5 = 0

n^2+(-21/2)*n+5 = 0

DELTA = (-21/2)^2-(1*4*5)

DELTA = 361/4

DELTA > 0

n = ((361/4)^(1/2)-(-21/2))/(1*2) or n = (-(-21/2)-(361/4)^(1/2))/(1*2)

n = 10 or n = 1/2

n in { 1/2, 10} 

n in { 1/2, 10 }

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