5/n=4-2n

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Solution for 5/n=4-2n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

5/n = 4-(2*n) // - 4-(2*n)

2*n+5/n-4 = 0

2*n^1+5*n^-1-4*n^0 = 0

(2*n^2-4*n^1+5*n^0)/(n^1) = 0 // * n^2

n^1*(2*n^2-4*n^1+5*n^0) = 0

n^1

2*n^2-4*n+5 = 0

2*n^2-4*n+5 = 0

DELTA = (-4)^2-(2*4*5)

DELTA = -24

DELTA < 0

n in { } 

n belongs to the empty set

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