5/t-3-30/(t-3)(t+3)=1

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Solution for 5/t-3-30/(t-3)(t+3)=1 equation: 



5/t-3-30/(t-3)(t+3)=1

We move all terms to the left:

5/t-3-30/(t-3)(t+3)-(1)=0



Domain of the equation: t!=0

t∈R





Domain of the equation: (t-3)(t+3)!=0

We move all terms containing t to the left, all other terms to the right

t-3)(t!=-3

t∈R



We add all the numbers together, and all the variables

5/t-30/(t-3)(t+3)-4=0

We use the square of the difference formula

t^2+5/t+9-4=0

We multiply all the terms by the denominator


t^2*t+9*t-4*t+5=0

We add all the numbers together, and all the variables

t^2*t+5t+5=0

Wy multiply elements

t^3+5t+5=0

We do not support etpression: t^3

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