5/x+1/x-3=x-2/x-3

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Solution for 5/x+1/x-3=x-2/x-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5/x+1/x-3 = x-(2/x)-3 // - x-(2/x)-3

5/x-x+1/x+2/x-3+3 = 0

8*x^-1-1*x^1 = 0

(8*x^0-1*x^2)/(x^1) = 0 // * x^2

x^1*(8*x^0-1*x^2) = 0

x^1

8-x^2 = 0

8-x^2 = 0

DELTA = 0^2-(-1*4*8)

DELTA = 32

DELTA > 0

x = (32^(1/2)+0)/(-1*2) or x = (0-32^(1/2))/(-1*2)

x = -2*2^(1/2) or x = 2*2^(1/2)

x in { -2*2^(1/2), 2*2^(1/2)} 

x in { -2*2^(1/2), 2*2^(1/2) }

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