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5/x+15/2x=5/4
We move all terms to the left:
5/x+15/2x-(5/4)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
5/x+15/2x-(+5/4)=0
We get rid of parentheses
5/x+15/2x-5/4=0
We calculate fractions
(-20x^2)/32x^2+160x/32x^2+240x/32x^2=0
We multiply all the terms by the denominator
(-20x^2)+160x+240x=0
We add all the numbers together, and all the variables
(-20x^2)+400x=0
We get rid of parentheses
-20x^2+400x=0
a = -20; b = 400; c = 0;
Δ = b2-4ac
Δ = 4002-4·(-20)·0
Δ = 160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{160000}=400$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-400}{2*-20}=\frac{-800}{-40} =+20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+400}{2*-20}=\frac{0}{-40} =0 $
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