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5/x+2+3/x-5=23/(x+2)(x+5)
We move all terms to the left:
5/x+2+3/x-5-(23/(x+2)(x+5))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+2)(x+5))!=0We add all the numbers together, and all the variables
x∈R
5/x+3/x-(23/(x+2)(x+5))-3=0
We multiply parentheses ..
-(23/(+x^2+5x+2x+10))+5/x+3/x-3=0
We calculate fractions
We do not support expression: x^3
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