5/x+2=10/2x+4

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Solution for 5/x+2=10/2x+4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5/x+2 = (10/2)*x+4 // - (10/2)*x+4

5/x-((10/2)*x)-4+2 = 0

5/x-5*x-4+2 = 0

5*x^-1-5*x^1-2*x^0 = 0

(5*x^0-5*x^2-2*x^1)/(x^1) = 0 // * x^2

x^1*(5*x^0-5*x^2-2*x^1) = 0

x^1

5-5*x^2-2*x = 0

5-5*x^2-2*x = 0

DELTA = (-2)^2-(-5*4*5)

DELTA = 104

DELTA > 0

x = (104^(1/2)+2)/(-5*2) or x = (2-104^(1/2))/(-5*2)

x = (2*26^(1/2)+2)/(-10) or x = (2-2*26^(1/2))/(-10)

x in { (2*26^(1/2)+2)/(-10), (2-2*26^(1/2))/(-10)} 

x in { (2*26^(1/2)+2)/(-10), (2-2*26^(1/2))/(-10) }

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