5/x+2=10/3x

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Solution for 5/x+2=10/3x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5/x+2 = (10/3)*x // - (10/3)*x

5/x-((10/3)*x)+2 = 0

(-10/3)*x+5/x+2 = 0

5*x^-1-10/3*x^1+2*x^0 = 0

(2*x^1-10/3*x^2+5*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^1-10/3*x^2+5*x^0) = 0

x^1

(-10/3)*x^2+2*x+5 = 0

(-10/3)*x^2+2*x+5 = 0

DELTA = 2^2-(4*5*(-10/3))

DELTA = 212/3

DELTA > 0

x = ((212/3)^(1/2)-2)/(2*(-10/3)) or x = (-(212/3)^(1/2)-2)/(2*(-10/3))

x = -3/20*((212/3)^(1/2)-2) or x = 3/20*((212/3)^(1/2)+2)

x in { -3/20*((212/3)^(1/2)-2), 3/20*((212/3)^(1/2)+2)} 

x in { -3/20*((212/3)^(1/2)-2), 3/20*((212/3)^(1/2)+2) }

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