If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
x = 0
x+3 = 0
x = 0
x = 0
x+3 = 0
x+3 = 0
x+3 = 0 // - 3
x = -3
x in (-oo:-3) U (-3:0) U (0:+oo)
5/x+1/x-2+3 = (8/(x+3))*(x-2) // - (8/(x+3))*(x-2)
5/x-((8/(x+3))*(x-2))+1/x-2+3 = 0
5/x-8*(x-2)*(x+3)^-1+1/x-2+3 = 0
(-8*(x-2))/(x+3)+5/x+1/x-2+3 = 0
(-8*x*(x-2))/(x*(x+3))+(5*(x+3))/(x*(x+3))+(1*(x+3))/(x*(x+3))+(-2*x*(x+3))/(x*(x+3))+(3*x*(x+3))/(x*(x+3)) = 0
5*(x+3)-8*x*(x-2)+1*(x+3)-2*x*(x+3)+3*x*(x+3) = 0
3*x^2-8*x^2-2*x^2+21*x+x-6*x+9*x+3+15 = 0
3*x^2-8*x^2-2*x^2+22*x-6*x+9*x+18 = 0
3*x^2-10*x^2+16*x+9*x+18 = 0
25*x-7*x^2+18 = 0
25*x-7*x^2+18 = 0
25*x-7*x^2+18 = 0
DELTA = 25^2-(-7*4*18)
DELTA = 1129
DELTA > 0
x = (1129^(1/2)-25)/(-7*2) or x = (-1129^(1/2)-25)/(-7*2)
x = (1129^(1/2)-25)/(-14) or x = (1129^(1/2)+25)/14
(x-((1129^(1/2)-25)/(-14)))*(x-((1129^(1/2)+25)/14)) = 0
((x-((1129^(1/2)-25)/(-14)))*(x-((1129^(1/2)+25)/14)))/(x*(x+3)) = 0
((x-((1129^(1/2)-25)/(-14)))*(x-((1129^(1/2)+25)/14)))/(x*(x+3)) = 0 // * x*(x+3)
(x-((1129^(1/2)-25)/(-14)))*(x-((1129^(1/2)+25)/14)) = 0
( x-((1129^(1/2)+25)/14) )
x-((1129^(1/2)+25)/14) = 0 // + (1129^(1/2)+25)/14
x = (1129^(1/2)+25)/14
( x-((1129^(1/2)-25)/(-14)) )
x-((1129^(1/2)-25)/(-14)) = 0 // + (1129^(1/2)-25)/(-14)
x = (1129^(1/2)-25)/(-14)
x in { (1129^(1/2)+25)/14, (1129^(1/2)-25)/(-14) }
| 4x+22=y | | 14/40-25/40 | | 6t+1.5t=7.5 | | 5y+4=5(.8y+2)-(6-y) | | 84/7-6/2 | | 0.3x-0.7x-7=1 | | 7/2y+5=8 | | 3(c+9)=3(c-4) | | 3/13+5/13 | | 7x^3-21x^2-1666x= | | 4(3+4x)-3=89 | | 2/3(3/2)=1 | | 8y^3-24y^2-224y= | | 3(28/13)-2(3/13)=6 | | 7x^2=126 | | 10-0.5d=14 | | 4x-6(2x)-16=0 | | 3(0.2x+1)=-1.8 | | 2.9x+57.9=34.9-8.6x | | wr=rw | | y/4-1/y=3/4 | | 4x+x-3=4x+7 | | 20(a+b)=20(b+a) | | x/3=12/9 | | 2t^2-11t+14=0 | | 4*x^(1/3)+5=29 | | 0.4-0.05x=-0.25 | | 2y^2-4y-8=-y^2+4 | | 2(x+3)-5=5x | | (6y+8)-(8y+7)= | | 19-2(3x+4y)= | | 5(-6+2x)=40 |