5/x+4+7/8=2x+3/3x+12

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Solution for 5/x+4+7/8=2x+3/3x+12 equation: 



5/x+4+7/8=2x+3/3x+12

We move all terms to the left:

5/x+4+7/8-(2x+3/3x+12)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: 3x+12)!=0

x∈R



We get rid of parentheses

5/x-2x-3/3x-12+4+7/8=0

We calculate fractions


63x^2/192x^2-2x+960x/192x^2+(-192x)/192x^2-12+4=0

We add all the numbers together, and all the variables

63x^2/192x^2-2x+960x/192x^2+(-192x)/192x^2-8=0

We multiply all the terms by the denominator


63x^2-2x*192x^2+960x+(-192x)-8*192x^2=0

We add all the numbers together, and all the variables

63x^2+960x-2x*192x^2+(-192x)-8*192x^2=0

Wy multiply elements

63x^2-384x^3-1536x^2+960x+(-192x)=0

We get rid of parentheses

63x^2-384x^3-1536x^2+960x-192x=0

We do not support expression: x^3

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